(x+4)^2=(-x+21)

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Solution for (x+4)^2=(-x+21) equation: 



(x+4)^2=(-x+21)

We move all terms to the left:

(x+4)^2-((-x+21))=0

We add all the numbers together, and all the variables

(x+4)^2-((-1x+21))=0



We calculate terms in parentheses: -((-1x+21)), so:

(-1x+21)

We get rid of parentheses

-1x+21

Back to the equation:

-(-1x+21)



We get rid of parentheses

(x+4)^2+1x-21=0

We add all the numbers together, and all the variables

x+(x+4)^2-21=0

We move all terms containing x to the left, all other terms to the right

x+(x+4)^2=21

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